v = X_C \\cdot i \\\\\\mathstrut\\\\\nv = X_C \\cdot C {dv \\over dt} \\\\\\mathstrut\\\\\nv = X_C \\cdot C j \\omega v \\\\\\mathstrut\\\\\n\\tag{5} \\boxed{X_C = {1 \\over {j \\omega C}}}<\/pre><\/div>\n\n\n\nCalculemos ahora la reactancia inductiva (XL<\/sub><\/em>):<\/p>\n\n\n\nv = X_L \\cdot i \\\\\\mathstrut\\\\\n{dv \\over dt} = X_L \\cdot {di \\over dt} \\\\\\mathstrut\\\\\nv = L {di \\over dt} \\\\\\mathstrut\\\\\n{di \\over dt} = {v \\over L} \\\\\\mathstrut\\\\\nj \\omega v = X_L \\cdot {v \\over L} \\\\\\mathstrut\\\\\n\\tag{6} \\boxed{X_L = j \\omega L}<\/pre><\/div>\n\n\n\nY ya est\u00e1 analizada matem\u00e1ticamente la respuesta del condensador y de la bobina en corriente alterna. Cuando estuve preparando esta entrada y me puse a emborronar papeles me di cuenta que aunque no era nada muy complejo si que era un tanto enrevesado dar con la soluci\u00f3n. Al final descubr\u00ed que si calculaba primero dv\/dt<\/em> todo se volv\u00eda trivial pues es lo \u00fanico que realmente hay que derivar, el resto son transformaciones y sustituciones m\u00e1s bien sencillas.<\/p>\n\n\n\nVolviendo atr\u00e1s cuando calculaba dv\/dt<\/em> (4) realizaba una transformaci\u00f3n de se\u00f1al cosenoidal a se\u00f1al senoidal. Si no hubiera hecho eso me habr\u00eda encontrado en un momento dado con la siguiente expresi\u00f3n:<\/p>\n\n\n\n{\\sin(\\omega t) \\over \\cos(\\omega t)} = \\tan(\\omega t)<\/pre><\/div>\n\n\n\nLo primero que nos damos cuenta es que no eliminamos de la expresi\u00f3n el tiempo, por lo que la reactancia variar\u00eda en funci\u00f3n del tiempo (t<\/em>) y sabemos que no es as\u00ed, var\u00eda en funci\u00f3n de la frecuencia (\u03c9<\/em>). Lo segundo es que sabemos que la tangente es una funci\u00f3n con puntos indeterminados que tienden a infinito, y esto tampoco es cierto porque la reactancia siempre tiene un valor concreto.<\/p>\n\n\n\nQuiero terminar esta entrada poniendo una vez m\u00e1s las ecuaciones que definen a los condensadores y a las bobinas, es algo que siempre me maravillar\u00e1:<\/p>\n\n\n\n
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